(F.2)Factorize: 9p^2-q^2-12p-4q

2007-11-15 12:45 am
請列式,thx!

回答 (5)

2007-11-15 1:18 am
✔ 最佳答案
9p^2 - q^2 - 12p - 4q
可寫成 9p^2 - q^2 - 12p - 4q +4 -4
即 9p^2 - 12p +4 - q^2 - 4q -4
= (3p-2)(3p-2) - (q+2)(q+2)
=(3p-2)^2 - (q+2)^2
2007-11-26 9:38 am
這答案格式絕不是 Factorize 要求的格式,或者叫「未做完」,反而「其他回答」有一些是正確的。
2007-11-15 1:38 am
9p^2-q^2-12p-4q
=3p(3p-4)-q(q+4)
參考: me
2007-11-15 1:26 am
9p^2-q^2-12p-4q

= (9p^2 -12p + 4) -4 - (q^2 + 4q + 4) +4

= (3p - 2)^2 - (q + 2)^2

= (3p + q)(3p - q - 4) [By a^2 - b^2 = (a+b)(a-b)]
參考: 自己
2007-11-15 1:23 am
9p^2-q^2-12p-4q
=(3p-q)(3p+q)-4(3p+q)
=(3p+q)(3p-q-4)
參考: 自己


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