F.2 Factorization
回答 (3)
2007-11-14 5:42 am
✔ 最佳答案
(2x-y)(a^2-b)-(b-a^2)(y-2x)=(2x-y)(a^2-b)+(a^2-b)(y-2x)
=(2x-y)(a^2-b)-(a^2-b)(2x-y)
= 0
2007-11-14 5:49 am
無錯..係=0
2007-11-14 5:43 am
=2xa^2-2xb-ya^2+yb-(by-2xb-ya^2+2xa^2)
=2xa^2-2xb-ya^2+yb-yb+2xb+ya^2-2xa^2
=2xa^2-2xa^2+2xb-2xb+ya^2-ya^2+yb-yb
=0
玩人嗎??
=2xa^2-2xb-ya^2+yb-yb+2xb+ya^2-2xa^2
=2xa^2-2xa^2+2xb-2xb+ya^2-ya^2+yb-yb
=0
玩人嗎??
收錄日期: 2021-04-13 18:12:15
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071113000051KK03896