Please teach and tell me how to do the questoins below.
1) (2-t)/4 -t = (2t-3)/5
2) (x-1)/2 = (x+1)/3 +1
3) 1-2 [ 3-(x/2 - 1)] = x/4 +1
4) 1/6[1/2(1-2n)+1/3] = n/3
Tell me amply, please. :)
S.1 Maths; Linear Equations (Quick) 20marks=]
2007-11-13 1:39 am
回答 (1)
2007-11-13 2:13 am
✔ 最佳答案
(2-t)/4 -t = (2t-3)/510-5t-20t=8t-12
22=33t
t=2/3
(x-1)/2 = (x+1)/3 +1
3x-3=2x+2+6
x=11
1-2 [ 3-(x/2 - 1)] = x/4 +1
1-2[4-(x/2)]=(x/4)+1
1-8+x=(x/4)+1
-28+4x=x+4
3x=32
x=32/3
1/6[1/2(1-2n)+1/3] = n/3
(1-2n)/2=1/3=2n
3-6n+2=12n
18n=5
n=5/18
參考: myself
收錄日期: 2021-04-24 00:58:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071112000051KK02223