Factorize
1.12x^2-27y^2
2.49+14m+m^2
3.8a^2-56a+98
4.16a^2-8abc+b^2c^2
急急急!數學!10!
2007-11-12 6:20 am
回答 (3)
2007-11-12 6:31 am
✔ 最佳答案
1. 3(4x^2 - 9y^2) = 3[(2x)^2 - (3y)^2]= 3(2x+3y)(2x-3y)
2. 49+14m+m^2
= 7^2 + 2(7)(m) + m^2
= (7+m)^2
3.8a^2-56a+98
= 2(4a^2 - 28a + 49)
= 2[(2a)^2 - 2(2a)(7) + 7^2]
= 2(2a-7)^2
4.16a^2-8abc+b^2c^2
= (4a)^2 - 2(4a)(bc) + (bc)^2
= (4a- bc)^2
2007-11-12 6:39 am
1. 12x^2-27y^2
=3(4x^2-9y^2)
=3(2x-3y)(2x+3y)
2.49+14m+m^2
=(m+7)^2
3.8a^2-56a+98
=2(4a^2-28a+49)
=2(2m-7)^2
4. 16a^2-8abc+b^2c^2
=(4a-bc)^2
=3(4x^2-9y^2)
=3(2x-3y)(2x+3y)
2.49+14m+m^2
=(m+7)^2
3.8a^2-56a+98
=2(4a^2-28a+49)
=2(2m-7)^2
4. 16a^2-8abc+b^2c^2
=(4a-bc)^2
參考: ME
2007-11-12 6:34 am
1.12x^2-27y^2
=3(4x^2 - 9y^2)
=3(2x+3y) (2x-3y)
2.49+14m+m^2
=(7+m) (7-m)
3.8a^2-56a+98
=2(4a^2-28a+49)
=2(2a-7)^2
4.16a^2-8abc+b^2c^2
=(4a)^2-2(4a)(bc)+(bc)^2
=(4a-bc)^2
希望幫到你la~~
=3(4x^2 - 9y^2)
=3(2x+3y) (2x-3y)
2.49+14m+m^2
=(7+m) (7-m)
3.8a^2-56a+98
=2(4a^2-28a+49)
=2(2a-7)^2
4.16a^2-8abc+b^2c^2
=(4a)^2-2(4a)(bc)+(bc)^2
=(4a-bc)^2
希望幫到你la~~
參考: me
收錄日期: 2021-04-13 18:12:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071111000051KK05173