Maths Question 非常急

2007-11-12 1:30 am

Find the general term for each sequence.[leave your answers in surd form if necessary]
T[2]=6,T[6]=96

回答 (3)

2007-11-12 2:22 am

✔ 最佳答案

你都冇講佢係等差數列定等比數列
6=aR^(2-1)=aR
96=aR^(6-1)=aR^5

a=6/R
96=(6/R)(R^5)
16=R^4
R=2
∴a=3

∴The general term is T(n)=3 x 2^(n-1)

參考: me

👍 0 👎 0

2007-11-16 9:31 pm

Good answer~~~

👍 0 👎 0

2007-11-12 1:43 am

T[2]=6
a+d = 6

T[6]=96
a+5d = 96
a+d+4d = 96
4d = 96-6
d= 22.5

a=6-d
a=-16.5

general term= -16.5+(n-1)(22.5)

👍 0 👎 0