(20點)搵人同我計下f2 的因式解因式分解幾條就

(a-b)x+(a-b)y
=(a-b)(x+y)

升左F3
唔係咁記得點計
不過都試下啦
錯唔好話我呀

(x-y)m+(y-x)n
=(x-y)m-(-y+x)n
=(x-y)m-(x-y)n
=(x-y)(m+n)

r(p-2q)-(p-2q)
=(p-2q)(r+1)

(n+25)-m(n+25)
=(n+25)(1-m)

(x-1)+2(1-x)
=(x-1)-2(-1+x)
=(x-1)-2(x-1)
=(x-1)(1-2)
=-2(x-1)

x(a-5)-y(5-a)
=-x(-a+5)-y(5-a)
=-x(5-a)-y(5-a)
=(5-a)(-x-y)

5(3m-n)²-5a(n-3m)
=5(3m-n)(3m-n)+5a(-n+3m)
=5(3m-n)(3m-n)+5a(3m-n)
=唔記得左2次方點做, 書應該有教, 你自己搵ANS

5(x-y)³-10(y-x)²
=5(x-y)(x-y)(x-y)-10(y-x)(y-x)
=5(x-y)(x-y)(x-y)+10(x-y)(x-y)
=唔記得左2次方點做, 書應該有教, 你自己搵ANS

(-a+b)(x-y)-(a+b)(x-y)
=-(a-b)(x+y)-(a+b)(x-y)
=-(a-b)²-(x-y)²

a. (a-b)(x+y)

b. (x-y)m+(y-x)n
=(x-y)m-(x-y)n
=(x-y)(m-n)

c. (p-2q)(r-1)

d. (n+25)(1-m)

e. (x-1)+2(1-x)
=x-1+2-2x
=1-x

f. x(a-5)-y(5-a)
=x(a-5)+y(a-5)
=(a-5)(x+y)

g. 5(3m-n)^2-5a(n-3m)
=5(3m-n)^2+5a(3m-n)
=5(3m-n)(3m-n+a)

h. 5(x-y)^3-10(y-x)^2
=5(x-y)^3-10(x-y)^2
=5(x-y)^2 (x-y-5)

i. (-a+b)(x-y)-(a+b)(x-y)
=(x-y)(-a+b-a-b)
=-2a(x-y)
=2a(y-x)

ab+a+b+1 =a(b+1)+(b+1)=(b+1)(a+1)
1+x-y-xy=x(1-y)+(1-y)=(x+1)(1-y)
aw+bw+a+b=w(a+b)+(a+b)=(a+b)(w+1)
cx+cy-y-x=c(x+y)-(x+y)=(x+y)(c-1)
ac+bc-ad-bd=ac-ad+bc-bd=a(c-d)+b(c-d)=(a+b)(c-d)
2p+ap+2q+aq=2p+2q+ap+aq=2(p+q)+a(p+q)=(2+a)(p+q)
ku-kv+3v-3u=k(u-v)-3(u-v)=(k-3)(u-v)
xy-ay+2x-2a=y(x-a)+2(x-a)=(x-a)(y+2)
st-3s-2t+6=s(t-3)-2(t-3)=(s-2)(t-3)
4xy-3y+3z-4xz=y(4x-3)-z(4x-3)=(4x-3)(y-z)
4ax+6ay-4bx-6by=2a(2x+3y)-2b(2x+3y)=2(a-b)(2x+3y)
15bx-3b+5ax-a=3b(5x-1)+a(5x-1)=(a+3b)(5x-1)
6mb-4ma-6na+9nb=2m(3b-2a)-3n(2a-3b)=(2m+3n)(3b-2a)
uv-u-v^2+v=u(v-1)-v(v-1)=(u-v)(v-1)

6a^2+6-4a-9a=6a^2-4a+6-9a=2a(3a-2)-3(3a-2)=(2a-3)(3a-2)
3x-y-6xy+2y^2=3x-6xy-y+2y^2=3x(1-2y)-y(1-2y)=(3x-y)(1-2y)
36h^2k+12k-3hk^2-144h=36h^2k+12k-3hk^2-144h=3hk(12h-k)-12(12h-k)=3(hk-4)(12h-k)
x^2+ax-bx+xy-by-ab=a(x-b)+x(x-b)+y(x-b)=(x-b)(a+x+y)
cy^2-dy^2+cy-c+d-dy=cy^2-dy^2+cy-dy-c+d=y^2(c-d)+y(c-d)-(c-d)=(c-d)(y^2+y-1)