2cos^2 x+sinx-1=0 x between0 -360度
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THANKS
slove the equation
2007-11-11 2:54 am
回答 (1)
2007-11-11 3:02 am
✔ 最佳答案
2cos2x + sinx – 1 = 0 (0≦ x≦ 360˚) 2(1 – sin2x) + sinx – 1 = 0
-2sin2x + sinx + 1 = 0
2sin2x – sinx – 1 = 0
(2sinx + 1)(sinx - 1) = 0
sinx = -1 / 2 or 1
x = 210˚, 330˚ or 90˚
參考: Myself~~~
收錄日期: 2021-04-13 14:24:58
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