factor 2x^2+12x+30=0 please?

your final equation should read

2x^2+2x-24=0

which factors to

(2x-6)(x+4)=0
so either
2x-6=0
or
x+4=0

so x=3 or -4

after x^2+7x+3= -x^2+5x+27
you should get
2x^2+2x-24
divide the whole equation by 2
x^2+x-12=0
(x-4)(x+3)

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2x^2+2x-24=0

(2x-6)(x+4)=0
2x-6=0
or
x+4=0
so x=3 or -4

what u do is factor the GCF:2(X^2+X-12)=0,then u factor the equation out but forget the 2 and it should come out as (x+4) and (x-3) which both need to be set to zero to get -4 and 3.

Y=x^2+7x+3 ....(1)
y=-x^2+5x+27 ....(2)

(1) - (2)
0 = x^2+7x+3 - (-x^2+5x+27 )
0 = x^2+7x+3 +x^2 -5x -27
0 = 2x^2 + 2x -24
divide by 2
0 = x^2 + x - 12
0 = (x - 3) (x + 4)

x= 3 or -4
if x = 3, y = 9+21+3 = 33
if x = -4, y = 16-28+3 = -9

The problem 2x^2+12x+30=0 as such, does not have a solution.
ax^2+bx+c=0
a=2 b=12 c=30
b^2-4ac=12^2-4(2)(30)
=144-240 <0 negative
There are no real solutions.
x=[-b + or - (b^2-4ac)]/2a

You did right to get to
x^2+7x+3= -x^2+5x+27, but you messed up the adding and subtraction a little. you will add x^2 to each side, that part is okay, but you are going to subtract 5x and subtract 27 from each side giving you
2x^2+2x-24=0, then you will divide by 2 as it suggests giving you
x^2+x-12=0, which will seperate out nicely to (x+4)*(x-3)=0. leaving x to be -4 or 3.

2x^2+2x-24
x=-4