Please Help!
Question:
The cost of honey is $0.12/ml. The cost of water is $0/02/ml. A drink of 1 L is made by mixing honey and water in the ratio 1:9 by volume. To enhance the honey flavour of the drink, the amount of water is reduced and the amount of honey is increased to make 1 L of drink. It is given that in the new ratio used, cost of honey:cost of water = 2:1. How much more honey should be added to make 1 L of new-taste drink? (Give the answer in mL and correct to 1 decimal place.)
Please help - Ratio and Rates
2007-11-10 5:09 am
回答 (1)
2007-11-10 5:23 am
✔ 最佳答案
Originally, in 1 L of drink, there is 100 ml honey and 900 ml water.In the new-taste drink, let x ml be the volume of honey and (1000-x) be the volume of water.
Cost of honey = 0.12x
Cost of water = 0.02(1000-x)
Ratio = 0.12x/0.02(1000-x) = 2/1
6x/(1000-x) = 2/1
6x = 2(1000-x)
8x = 2000
x = 250
Therefore, there is 250 ml honey in the new-taste drink.
Hence (250-100) = 150 ml honey should be added to make 1 L of new-taste drink.
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