1.find the second derivative if 3x^2 + 2xy^2 = 1
Ans = (3y/4x^2) - (9/4y^3)
2. Let y= Asinx + Bcosx, where A and B are non-zero constants.
dy/dx = Acosx - Bsinx
d2y/dx2 = -Asinx- Bcosx
If 3(d2y/dx2) - 2(dy/dx) +6y = -13cosx, find A and B.
Ans : A=2,B= -3
3.y = sin(x+y)
find dy/dx.
hence show that [1-cos(x+y)](d2y/dx2) + y[1+dy/dx]^2=0
diffentiation
2007-11-09 2:29 am
回答 (1)
2007-11-09 5:42 am
✔ 最佳答案
As follows~圖片參考：http://i204.photobucket.com/albums/bb125/jasonchan424/971.jpg
圖片參考：http://i204.photobucket.com/albums/bb125/jasonchan424/972.jpg
圖片參考：http://i204.photobucket.com/albums/bb125/jasonchan424/973.jpg
參考: ME
收錄日期: 2021-04-13 14:23:15
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