S.2 maths -- Changing Subject

6/ a/h + a/k = k
a/h = k - a/k
a/h = (k^2-a)/k
a/(k^2-a) = h/k
h = a*k/(k^2-a)
7/2bf = bg +4
2bf - bg = 4
b(2f - g) = 4
b = 4/(2f - g)
8/k =pv/t + s
k - s = pv/t
t(k - s) = pv
p = t(k - s)/v
10/ s=a/1 + r
s - r = a

6)a/h+a/k=k


---------a/h=k-a/k--------將a/k調過去,使h獨自在一邊.


---------1/h=(k-a/k)/a---------/a,使h獨自在一邊


------------h=a/(k-a/k)----------e.g.:1/a=b,a=1/b



7)2bf = bg +4


2bf-bg=4－－－－－－將bg調走，使有ｂ項的在一起


b(2f-g)=4－－－－－－因式分解


－－b=4/(2f-g)－－－－將２ｆ－ｇ調去，完成


8) K = pv / T + S


Ｋ/pv=1/(T+S)


1/pv=1/(T+S)K-----------使ｐ獨自在一邊


pv=TK+SK－－－－－－－－e.g.:1/b=1/a,b=a


p=(TK+SK)/v-----------------------finish


what do u want in the 10s????

if u want a ,

10) S = a /1+r


－1/a=1/S+Sr


a=S+Sr


a=S(1+r)


if u want r,


10)S=a/1+r


1+r=a/S


r=1+a/S

so, thats all of it!!!

2008-01-21 17:40:42 補充：
cheap!!!

6) a/h + a/k = k [h]
a/h = k - a/k
h/a = k/k-a
h = ak/k-a

7) 2bf = bg +4 [b]
2bf - bg = 4
b(2f-g) = 4
b = 4/(2f-g)

8) K = pv / T + S [p]
K-S = pv / T
KT-ST= pv
(KT-ST) / v = p

10) S = a /1+r
S+Sr = a 如果要轉a做subject
Sr = a-S
r = (a-S) / S 如果要轉r做subject

2007-11-07 20:34:05 補充：
6)錯左6) a/h a/k = k [h] a/h = k - a/k h/a = 1 / ( k - a/k) h = a / ( k - a/k)

6)a/h+a/k=k
a/h=k-a/k
1/h=(k-a/k)/a
h=a/(k-a/k)

7) 2bf = bg +4
2bf-bg=+4
b(2f-g)=+4
b=4/(2f-g)

8) K = pv / T + S
1/pv=1 / (T + S)K
pv=TK+SK
p=(TK+SK)/v

10) S = a /1+r [a]
1/a=1/S+Sr
a=S+Sr

10) S = a /1+r [r]
1+r=a/S
r=1 + a/S

6. a/h +a/k =k
a/h= k - a/k
h = a/(k-a/k)
7. 2bf = bg + 4
2bf - bg = 4
b( 2f-g) =4
b = 4/(2f-g)
8. k = pv/t + s
k-s = pv/t
(k-s)t = pv
p = (k-s)t/v
10. which one is the subject???