Lim [ 2x - ( 4(x^2) + x ]^(1/2)
x-> infinity
Explaination Please !
Find the limit
2007-11-07 1:14 pm
回答 (1)
2007-11-07 5:15 pm
✔ 最佳答案
Do you mean 2x - [ 4(x^2) + x ]^(1/2) ?2x - [4(x^2) + x ]^(1/2)
={2x -[ 4(x^2) + x ]^(1/2)} { 2x + [4(x^2) + x ]^(1/2)} /{2x + [4(x^2) + x ]^(1/2)}
= [4x^2 - (4x^2 + x)] /{2x + [4(x^2) + x ]^(1/2)}
= -x /{2x + [4(x^2) + x ]^(1/2)}
=-1/{2 + [4 + 1/x]^(1/2)
Take x -> infinity, we get the limi = -1/(2 + 4) = -1/6
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