Math....Question

2007-11-07 4:17 am
1. 2x-6y/3y-x
2. -x^2+1/x+1
3. 2p-10r/r^2÷3p-15r/6pr

回答 (1)

2007-11-07 4:43 am
✔ 最佳答案
2x-6y/3y-x
= 2x-6y/-(x-3y)
=2(x-3y)/-(x-3y)
=2/-1
=- 2/1
2. -x^2+1/x+1
=- (x)(x+1)/x+1
= -x
3. 2p-10r/r^2 ÷ 30-15r/6pr
= 2p-10r/r^2 ÷ 6pr/3p-15r
= 2(p-5r)/r^2 ÷ 6pr/3(p-5r)
= (2)(6p)/(r)(3)
= (2)(2p)/r
= 4p/r




2007-11-07 12:09:14 補充:
第1題:=- 2/1= -2
參考: me


收錄日期: 2021-04-13 14:21:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071106000051KK03307

檢視 Wayback Machine 備份