有幾條數學.要有步驟ar...我吾識做...help ME..急!!
要有步驟ar..
1.(m-1)(m-6)
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2.(2y-5)(y+7)
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3.(7z-1)(z-7)
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4.(4+c)(5-c)
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5.(5m+4n)(m-4n)
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6.(3x-2y)(-3y-2x)
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回答 (3)
✔ 最佳答案
1.(m-1)(m-6)
=m^2-6m-m+6
=m^2-7m+6
2.(2y-5)(y+7)
=2y^2+14y-5y-35
=2y^2+9y-35
3.(7z-1)(z-7)
=7z^2-49z-z+7
=7z^2-50z+7
4.(4+c)(5-c)
=20-4c+5c-c^2
=20+c-c^2
5.(5m+4n)(m-4n)
=5m^2-20mn+4mn-16n^2
=5m^2-16mn-16n^2
6.(3x-2y)(-3y-2x)
= -9xy-6x^2-6y^2+4xy
=-6x^2-6y^2-5xy
參考: /
1.X
2.(2y-5)(y+7)
=2y-5xy+7
=2y+yx5+7
=3yx12
3.(7z-1)(z-7)
=7z-1xz-7
=7z-zx1-7
=6zx-1
4.(4+c)(5-c)
=4+cx5-c
=4+5xc-c
=9
5.(5m+4n)(m-4n)
=5m+4nxm-4n
=5m+mx4n-4n
=6m
6.X
參考: me
1. (m-1)(m-6)
= m(m-6)-(m-6)
= m^2-6m-m+6
= m^2-7m+6
2. (2y-5)(y+7)
= 2y(y+7)-5(y+7)
= 2y^2+14y-5y-35
= 2y^2+9y-35
3.(7z-1)(z-7)
= 7z(z-7)-(z-7)
= 7z^2-49z-z+7
= 7z^2-50z+7
4.(4+c)(5-c)
= 4(5-c)+c(5-c)
= 20-4c+5c-c^2
= 20+c-c^2
5.(5m+4n)(m-4n)
= 5m(m-4n)+4n(m-4n)
= 5m^2-20mn+4mn-16n^2
= 5m^2-16mn-16^2
6.(3x-2y)(-3y-2x)
= 3x(-3y-2x)-2y(-3y-2x)
= -9xy-6x^2+6y^2+4xy
= -5xy-6x^2+6y^2
參考: 自己 =]
收錄日期: 2021-04-23 20:25:45
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