PQ+QR=?
2.GIVEN THAT THE AREA OF A SQUARE WOODEN BOARD IS 125CM2, FIND THS LENGTH OF THER DIAGONAL OF THE BOARD.( LEAVE YOUR ANSWER IN A SQUARE ROOT FORM)
更新1:
第一題果到，PQ=QR
2題簡單MATH QUESTION(中2)
2007-11-06 2:30 am
1. PQ2 +QR 2 = 16
PQ+QR=?
2.GIVEN THAT THE AREA OF A SQUARE WOODEN BOARD IS 125CM2, FIND THS LENGTH OF THER DIAGONAL OF THE BOARD.( LEAVE YOUR ANSWER IN A SQUARE ROOT FORM)
PQ+QR=?
2.GIVEN THAT THE AREA OF A SQUARE WOODEN BOARD IS 125CM2, FIND THS LENGTH OF THER DIAGONAL OF THE BOARD.( LEAVE YOUR ANSWER IN A SQUARE ROOT FORM)
回答 (2)
2007-11-07 7:26 am
✔ 最佳答案
Let x = PQ =QRX^2 + X^2 =16
2X^2 =16
X^2=8
X= sqrt( 8)
PQ +QR = 2X = 2 sqrt (8) = 4 sqrt( 2)
2. Let y cm be the side of the square.
y^2 =125
Let z cm be the length of the diagonal
z^2= y^2 + y^2
z^2 =2 y^2
z^2 =2 * 125
z^2 =250
z= sqrt(250)
2007-11-06 4:08 am
我有兩個擬問??
PQ2=(PQ)^2...???
QR 2=(QR)^2...???
IF YES, THEN: (PQ)^2+(QR)^2=16
(PQ+QR)^2-2PQ^2R=16
PQ+QR=開方（16-2PQ^2R）
PQ2=(PQ)^2...???
QR 2=(QR)^2...???
IF YES, THEN: (PQ)^2+(QR)^2=16
(PQ+QR)^2-2PQ^2R=16
PQ+QR=開方（16-2PQ^2R）
收錄日期: 2021-04-23 22:10:41
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