2題簡單MATH QUESTION(中2)

👨🏻‍🏫 學術台數學

2007-11-06 2:30 am

1. PQ2 +QR 2 = 16
PQ+QR=?

2.GIVEN THAT THE AREA OF A SQUARE WOODEN BOARD IS 125CM2, FIND THS LENGTH OF THER DIAGONAL OF THE BOARD.( LEAVE YOUR ANSWER IN A SQUARE ROOT FORM)

更新1:

第一題果到，PQ=QR

回答 (2)

用戶46949

2007-11-07 7:26 am

✔ 最佳答案

Let x = PQ =QR
X^2 + X^2 =16
2X^2 =16
X^2=8
X= sqrt( 8)
PQ +QR = 2X = 2 sqrt (8) = 4 sqrt( 2)

2. Let y cm be the side of the square.
y^2 =125

Let z cm be the length of the diagonal
z^2= y^2 + y^2
z^2 =2 y^2
z^2 =2 * 125
z^2 =250
z= sqrt(250)

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用戶92916

2007-11-06 4:08 am

我有兩個擬問??
PQ2=(PQ)^2...???
QR 2=(QR)^2...???

IF YES, THEN: (PQ)^2+(QR)^2=16
(PQ+QR)^2-2PQ^2R=16
PQ+QR=開方（16-2PQ^2R）

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