F.4 Maths

2007-11-05 1:05 am
Shows a semicircle,ABP and DCP are straight lines.Angle BPD=30度 and Angle BDP=20度
Find angle DAC and angle CBD


http://i240.photobucket.com/albums/ff164/walkinginthesang/e64e2fe5.jpg?t=1194166905

回答 (2)

2007-11-05 3:54 am
✔ 最佳答案
As follows:

圖片參考:http://i240.photobucket.com/albums/ff164/walkinginthesang/e64e2fe5.jpg?t=1194166905

I think you have missed out point B where AB is the diameter of the circle.
∠BPD + ∠BDP = ∠ DBA ( ext. ∠ of △ )
20* + 30* = ∠ DBA
∠ DBA = 50*
∠ DBA = ∠ DCA = 50* ( ∠s in the same segment )
∠ ADB = 90* ( ∠ in semi - circle )
∠ ADC + ∠ DCA + ∠ DAC = 180* ( ∠ sum of △ )
( 90* + 20* ) + 50* + ∠ DAC = 180*
∠ DAC = 20*
∠ DAC = ∠ CBD = 20* ( ∠s in the same segment )
參考: My Maths Knowledge
2007-11-09 3:32 am
∠ DAC = ∠ CBD = 20*


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