1)The age of Jason is twice that of Jacky, but is only half that of Jenny. If the sum of their ages is 84, how old is each of them?
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Maths(ratio,,20 fun)
2007-11-03 4:35 am
回答 (2)
2007-11-03 4:40 am
✔ 最佳答案
設Jacky係y歲..咁Jason偽2y歲...Jenny係4y歲..the sum of their ages is 84
y+2y+4y=84
7y=84
y=12
soJacky係12歲..咁Jason偽24歲...Jenny係48歲..
2007-11-03 4:40 am
Let x be the age of Jackson
x/2 + x + 2x = 84
7x/2 = 84
x = 24
Therefore Jacky, Jackson, Jenny are 12 , 24, 48 years old respectively
2007-11-03 19:42:52 補充：
Alternate method:Age of Jacky : Age of Jackon : Age of Jenny = 1/2 : 1 : 2 = 1 : 2 : 4age of Jacky = 84x1/(1+2+4) = 12 age of Jackson = 84x2/(1+2+4) = 24 age of Jenny = 84x4/(1+2+4) = 48
x/2 + x + 2x = 84
7x/2 = 84
x = 24
Therefore Jacky, Jackson, Jenny are 12 , 24, 48 years old respectively
2007-11-03 19:42:52 補充：
Alternate method:Age of Jacky : Age of Jackon : Age of Jenny = 1/2 : 1 : 2 = 1 : 2 : 4age of Jacky = 84x1/(1+2+4) = 12 age of Jackson = 84x2/(1+2+4) = 24 age of Jenny = 84x4/(1+2+4) = 48
參考: myself
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