中二數學(~急~)

1.xyp-xyp+3p-3p
=p(xy-xy+3-3)
=p(0+0)
=p(0)
=0

你有幾個計算方法︰
1.xyp-xyp+3p-3p
=xyp(1-1)+3p(1-1)
=xyp(0)+3p(0) ~0乘任何數都係0
=0

2. xyp-xyp+3p-3p
=p(xy-xy+3p-3p)
=p(0)
=0

3.xyp-xyp+3p-3p ~xyp-xyp=0 ; 3p-3p=0 ， so
=0

2007-11-03 20:34:33 補充：
更正第二題︰2 .xyp-xyp+3p-3p= p(xy-xy+3-3)= p(0)= 0not上面的第二題

xyp-xyp+3p-3p
=xyp-xyp+3p-3p (對消)
=0

xyp-xyp+3p-3p
=xyp-3p-xyp+3p
=p(xy-3)-p(xy-3)
=(xy-3)(p-p)
=0(xy-3)

要識多項式,先要識單項式
單項式即是一個代數式或一個數字或一個變數
例如:1,-5,0.3ab.........
多項式即是由兩個單項式相加而成
例如:y+5,3k.......
在多項式中,每個單項式稱為該多項式的項,而只含數字的項稱為常數項,一個多項式中最高次項的數,便是該多項式的次數
例如:3k-9ac+4是一個二次多項式,常數項:4
因式分解:
1.xyp-xyp+3p-3p
=p(xy-xy+3-3)
=p(xy-xy)
=p(0)
=0

xyp(1-1)+3p(1-1)
=xyp(0)+3p(0)
=0

xyp-xyp+3p-3p
=0

xyp-xyp+3p-3p
=p(xy-xy+3-3)
=0

xyp-xyp+3p-3p
=p(xy-xy+3-3)

1.xyp-xyp+3p-3p
=p(xy-xy+3-3)
=p(0+0)
=p(0)
=0