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[log(3x + 4)]/logx = 2
logarithm question
2007-11-02 7:03 am
回答 (1)
2007-11-02 7:12 am
✔ 最佳答案
[log(3x + 4)]/logx = 2 log(3x + 4) = 2 log x
log(3x + 4) = log (x^2)
3x + 4 = x^2
x^2 - 3x - 4 = 0
(x - 4)(x + 1) = 0
x = 4 or x = -1 (rejected because x > 0)
收錄日期: 2021-04-13 14:18:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071101000051KK04374