L.C.M一題

2007-11-01 5:37 am
x-y,2(y-x)^2,3(x-y)^3

佢地個L.C.M係 6(x-y)^3

但係點計到牙??
(y-x)變到做(x-y)咩?

回答 (2)

2007-11-01 5:44 am
✔ 最佳答案
睇黎你唔明係個2(y-x)^2姐

2(y-x)^2
=2(y-x)(y-x)
=2(-x+y)(-x+y)
=2[-(x-y)][-(x-y)]
=2(x-y)^2

咁宜家你明唔明??
2007-11-01 5:44 am

(y-x) = - (x-y) 嘛
所以 (y-x)^2 = (x-y)^2

x-y, 2(y-x)^2, 3(x-y)^3 的 LCM
= x-y, 2(x-y)^2, 3(x-y)^3 的 LCM
= 6 (x-y)^3 囉


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