請列式
(2x-y)^2-x(-2y)^2
是甚麼?
thank you!
一條有趣的問題
2007-11-01 2:52 am
回答 (3)
2007-11-01 3:04 am
✔ 最佳答案
(2x-y)^2-x(-2y)^2=(2x)^2-2(2x)(y)+(y)^2-x(4y^2)
=4x^2-4xy+y^2-4xy^2
=-4xy^2+4x^2-4xy+y^2
2007-11-01 11:23 pm
(2x-y)^2-x(-2y)^2
= (4x^2 - 4xy + y^2) - x(4y^2)
= 4x^2 - 4xy^2 - 4xy + y^2
= (4x^2 - 4xy + y^2) - x(4y^2)
= 4x^2 - 4xy^2 - 4xy + y^2
2007-11-01 3:09 am
唔知你要計乜野,但係就咁計就計到
(4x^2)-(4xy)+(y^2)-(4xy^2)
(4x^2)-(4xy)+(y^2)-(4xy^2)
收錄日期: 2021-04-23 22:36:46
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071031000051KK02871