PURE MATHS FUNCTION一問? 急!!!!

(i) f(0+0) = f(0) + f(0) + 0*0
f(0) = 2f(0)
f(0) = 0
(ii) As it is continuous at x = 0, lim(h→0) f(h) = f(0) = 0
For any real values of x, lim(h→x) f(h) = lim(a→0)f(x+a) [Let a = h-x, hence h = a+x]
= lim(a→0)[f(x)+f(a) +ax]
= f(x) + 0 + (0)(x)
= f(x) for all real values of x.
Hence f is continuous for all real values of x.

f(0)=0
f*0*0=0*0
F0*2=F0*
F=0

ans：

f(0)=0
f*0*0=0*0
F0*2=F0*
F=0