(3x^2y)^3
________
9x^3y^4
數學題~好急 指數
2007-10-30 8:31 pm
回答 (4)
2007-10-30 8:44 pm
✔ 最佳答案
. (3x^2y)^3. ________
. 9x^3y^4
. 3^3 * x^(2*3) * y^3
. = ________________
. 9x^3 * y^4
. 27 x^6 y^3
. = ____ * _____ * ______
. 9 x^3 y^4
. = 3 * x^(6-3) * y^(3-4)
. = 3x^3 *y^(-1)
. = 3x^3 / y
2007-10-30 11:24 pm
(3x^2y)^3
________
9x^3y^4
27x^8y^3
________
9x^3y^4
3x^5
____
y
________
9x^3y^4
27x^8y^3
________
9x^3y^4
3x^5
____
y
2007-10-30 9:35 pm
= 3x^3 / y
2007-10-30 9:21 pm
=(27x^6y^3)/(9x^3y^4)
=(27/9)(x^6/x^3)(y^3/y^4)
=3x^3y^-1
=(3x^3)/y
=(27/9)(x^6/x^3)(y^3/y^4)
=3x^3y^-1
=(3x^3)/y
參考: me
收錄日期: 2021-04-28 14:53:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071030000051KK01011