數學題,,,

2007-10-30 5:44 am
13.Show that f(x,y) = ky(2y – x) for x = 0, 3; y = 0, 1, 2 cannot serve as the joint probability distribution of two random variables for any value of k.

回答 (2)

2007-10-30 6:25 am
✔ 最佳答案

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2007-10-30 6:29 am
f(x,y) can serve as the joint probability distribution of two random variables for any value of k if and only if the sum of f(x,y) for x=0,1; y=0,1,2 equals 1, and f(x,y) >= 0 for every possible values of x and y.

f(0,0)=0
f(0,1)=k(2-0)=2k
f(0,2)=2k(4-0)=8k
f(3,0)=0
f(3,1)=k(2-3)=-k
f(3,2)=2k(4-3)=2k

if k positive, f(3,1) < 0
if k negative, f(0,1) < 0
if k is zero, sum of f(x,y) for x=0,3; y=0,1,2 is not equal to 1

therefore, f(x,y) cannot serve as the joint probability distribution for any value of k


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