✔ 最佳答案
Let the min mass of ice required be mkg and assume no enery lost to the surroundings during mixing.
By E = ml, the energy required for the ice to melt completely:
E = ( 3.34 x 10^5 )m
Then by E = mc△T,
( 3.34 x 10^5 )m + m ( 4200 )( 15 - 0 ) = 0.3 ( 4000 )( 68 - 15 )
397000m = 63600
m = 0.160kg ( cor. to 3 s.f. )
So the mass of ice is 0.160kg.