what to do the question 13c & 14b of EXERCISE 2.3(p.45) of New Way Mathematics & statistics (pulished by Manhattan)
ps: please give the steps
math&stat怎樣做?
2007-10-29 11:26 pm
回答 (1)
2007-10-30 6:08 am
✔ 最佳答案
13C3√6
=(8 - 2)1/3次方
=8 1/3次方 X (1 - 2 X 1/8)1/3次方
=2[1 - 2/3(1/8) - 4/9(1/8)2次方 - 40/81(1/8)3次方 + ...] <-- FROM A
=1.82 (2位小數)
14B
PUT X =1/9
√1 + 1/9 / 1 - 1/9
=1 + 1/9 +1/2(1/9)2次方 + 1/2(1/9)3次方 +... <---FROM A
∴ √5/4 = 1 + 1/9 +1/2(1/9)2次方 + 1/2(1/9)3次方 + ...
∴ √5 = 2[1 + 1/9 +1/2(1/9)2次方 + 1/2(1/9)3次方 + ...]
= 2.236 (4 sig.fig.)
唔知你睇唔睇得明- -
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