x^4+2x^3-x^2-2x
a^2-b^2+2bc-c^2
^ =代表D數係次方
因式分解2題
2007-10-29 3:29 am
回答 (4)
2007-10-29 3:46 am
x^4+2x^3-x^2-2xa^2-b^2+2bc-c^2
=(x^4-x^2)+(2x^3-2xa^2)-(b^2-2bc+c^2)
=(x^2-X)(x^2+X)+2X(X^2-a^2)-(b-c)^2
=(x^2-X)(x^2+X)+2X(X-a)(x+a)-(b-c)^2
=(x^4-x^2)+(2x^3-2xa^2)-(b^2-2bc+c^2)
=(x^2-X)(x^2+X)+2X(X^2-a^2)-(b-c)^2
=(x^2-X)(x^2+X)+2X(X-a)(x+a)-(b-c)^2
2007-10-29 3:39 am
x^4+2x^3-x^2-2x=x(x-1)(x+1)(x+2)
a^2-b^2+2bc-c^2=(a-b+c)(a+b-c)
a^2-b^2+2bc-c^2=(a-b+c)(a+b-c)
2007-10-29 3:38 am
x^4+2x^3-x^2-2x
=x^2(x^2-1)+2x(x^2-1)
=(x^2+2x)(x^2-1)
a^2-b^2+2bc-c^2
=a^2-(b-c)^2
=(a-b-c)(a+b-c)
=x^2(x^2-1)+2x(x^2-1)
=(x^2+2x)(x^2-1)
a^2-b^2+2bc-c^2
=a^2-(b-c)^2
=(a-b-c)(a+b-c)
2007-10-29 3:37 am
1(
x^4+2x^3-x^2-2x
=x^2(x^2-1)+2x(x^2-1)
=(x^2-1)(x^2+2x)
2(
a^2-b^2+2bc-c^2
=a^2-(b-c)^2
=(a-b+c)(a+b-c)
x^4+2x^3-x^2-2x
=x^2(x^2-1)+2x(x^2-1)
=(x^2-1)(x^2+2x)
2(
a^2-b^2+2bc-c^2
=a^2-(b-c)^2
=(a-b+c)(a+b-c)
收錄日期: 2021-04-13 19:41:10
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https://hk.answers.yahoo.com/question/index?qid=20071028000051KK04277