一條F.1數學

2007-10-29 2:06 am
農場內有一些雞和兔
三分之一的兔子只得三隻腳...
若雞和兔共有35個頭和90隻腳..
求雞和四腳兔(即正常兔)分別有多少隻

回答 (2)

2007-10-29 2:44 am
✔ 最佳答案
Let X = 雞
Let Y = 兔

X + Y = 35 (一共有35隻)

2X + ((2/3 Y) x 4) + ((1/3 Y) x 3) = 90 (兩隻腳的雞 + 4隻腳的正常兔 + 3隻腳的不正常兔 共有90隻腳)

(70 - 2Y) + 8Y/3 + 3Y/3 = 90

(210 - 6Y)/3 + 8Y/3 + 3Y/3 = 90

210 - 6Y + 8Y + 3Y = 270

5Y = 60

Y=12

所以 X = 23 (雞)
正常兔 = 12 x 2/3 = 8 (正常兔)
2007-10-29 2:46 am
let x be no. of chicken
y be no. of 4-leg rabbits
z be no, of 3-leg rabbits


x+y+z = 35 (1)
2x+4y+3z = 90 (2)
z = (y+z) / 3 (3)

from (3)
z = y/3 + z/3
2z/3 = y/3
z = y/2

put z = y/2 into (1)
x+y+y/2 = 35
x+3y/2 = 35
x = 35-3y/2

put x = 35-3y/2 into (2)
2(35-3y/2)+4y+3(y/2) = 90
70-3y+4y+3y/2 = 90
2.5y = 20
y = 8

z = 4

x = 23

雞 : 23
四腳兔 : 8


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