數學1題~~~(未字數)

👨🏻‍🏫 學術台數學

Elaine

2007-10-28 11:59 pm

[(2x-6)+(1/2x)]2=28
要步驟~~~thx

回答 (7)

AJJS

2007-10-30 3:12 am

[(2x-6)+(1/2x)]2=28
(2x-6+1/2x)2=28
4x-12+x=28
4x+x=28+12
5x=40
x=8

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mantao

2007-10-29 12:15 am

2(2x-6)+2(1/2x)=28
4x-12+x=28
5x-12=28
5x=28+12
5x=40
x=8

參考: me

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[匿名]

2007-10-29 12:14 am

2(2x-6)+2(1/2x)=28
4x-12+x=28
5x-12=28
5x=28+12
5x=40
x=8

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semiii

2007-10-29 12:07 am

應該係咁
[(2x-6)+(1/2x)]2=28
(2x-6)+(1/2x)=28/2
2x-6+1/2x=14
2x+1/2x=14+6
5/2x=20
x=20*2/5
x=8

參考: 自己

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用戶103740

2007-10-29 12:07 am

[(2x-6)+(1/2x)]2=28
4x-12+x=28
5x=40
x=8

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用戶213779

2007-10-29 12:06 am

[(2x-6)+(1/2x)]2=28
4x-12+x=28
5x=40
x=8

參考: me

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LCS

2007-10-29 12:05 am

[(2x-6)+(1/2x)]2=28
2(2X+6)+2(1/2X)=28
4X+12+2/4X=28
4X+16=112
4X=96
X=24

參考: ME

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