Maths ERGENT HW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!20pts

f(x) = x99 + k

a. By remainder theorem,

f(-1) = 1

(-1)99 + k = 1

-1 + k = 1

k = 2


b. Let g(x) be 999 + 2

When g(x) is divided by 10, which is 9 + 1

The remainder is 1 (by part a)

So, when 999 is divided by 10, the remainder is 8.

2007-10-28 11:50:59 補充：
Sorry for a typing mistake. The answer of part b should be remainder = 9It is because 11 - 1 - 1 = 9 not 8