easy maths

2007-10-27 10:17 pm
1.log 3 (log 2 2)<-------前面個個3係3進制..第一個2係2進制
答:0

2.log 6 (3+log 3 27)<-------前面個個6係6進制..第二個既3係3進制
答:1

3.log 2 16+log 3 1/9 -log 5 √125<----------2,3,5都係進制
答:1/2

4.if log 3=h and log 5=k,express the following in terms of h and k.
a)log 40
b)log 15^4

回答 (2)

2007-10-27 10:24 pm
✔ 最佳答案
1. log 3 (log 2 2) = log 3 (1) = log 3 (3^0) = 0
2. log 6 (3+log 3 27) = log 6 (3+ log 3 3^3) = log 6 (3+3) = log 6 (6) = 1
3. log 2 16+log 3 1/9 -log 5 √125
= log 2 2^4 + log 3 3^(-2) - log 5 5^(3/2)
= 4 - 2 - 3/2
= 1/2
4.(a) log 40 = log (1000/25) = log 1000 - log 25 = 3 - log 5^2 = 3-2log 5 = 3-2k
(b) log 15^4 = 4 log 15 = 4log(3x5) = 4[log 3+ log 5]
=4(h+k)
2007-10-27 10:31 pm
1. log3 * log2 2^1
= log3 1
= log 3 3^0
= 0

2. log6 (3+ log3 3^3)
=log6 (3+ 3)
= log6 6^1
= 1


3. log2 2^4 + log3 3^(-2) - log5 5^(3/2)
= 4 -2 -3/2
= 1/2


4a log40
=log 5*8

=log[5*1000/(5*5*5)]
=k + 3 -k - k - k
= 3-2k
4b log 15^4
=log (3*5)^4
=log [3*3*3*3*5*5*5*5]
= 4h+4k


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