-b2次-25b-150

2007-10-27 9:52 am
-b+25b-150
究竟係
(b-15)(b-10)=0
b=15 b=10
定係
(b-30)(-b+5)=0
b=30 -b=-5
b=5

回答 (2)

2007-10-27 9:59 am
✔ 最佳答案
-b^2 + 25b - 150
= - (b^2 - 25b + 150)
= - (b - 15)(b - 10)

-b^2 + 25b - 150 = 0
- (b - 15)(b - 10) = 0
b = 15 or b = 10
2007-10-27 10:01 am
(b+15)(b+10)=0


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