數學問題1條(代數)(須列式)(10分)

2007-10-26 9:28 pm
求x的值

120 = x ( 5x - 1 )

回答 (5)

2007-10-26 9:39 pm
✔ 最佳答案
120=5x^2 - x
5x^2-x-120=0
(5x+24) (x-5)=0
所以
5x+24=0 or x-5=0
x=-24/5 or x=5
參考: MEME
2007-10-27 6:33 am
1.
120 = x ( 5x - 1 )
120 = 5x->2 - x
5x->2 - x - 120 = 0
x = [1± √(1 - 4 X 5 X -120)] / (2 X 5)
x = 5
參考: me
2007-10-26 9:56 pm
120 = x ( 5x - 1 )
=> 120 = 5x^2 - x
=> 5x^2 - x - 120 = 0
=> (5x + 24)(x - 5) = 0
=> x = -24/5 or 5
2007-10-26 9:46 pm
120 = x ( 5x - 1 )
120 = 5x^2 - x
5x^2 - x - 120 = 0
x = [1± √(1 - 4 X 5 X -120)] / (2 X 5)
x = 5 or -4.8

x = your unknown 未知數
^2 = square 2次方
X = multiple sign 乘號
參考: quatratic formula
2007-10-26 9:41 pm
120=X(5X-1)
120 (5X-1)
------= --------
5 5

24=2X-1

24 2X-1
---- = --------
2 2

12=X-1

12+1=X-1+1
13=X
x=13


收錄日期: 2021-04-13 14:10:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071026000051KK01240

檢視 Wayback Machine 備份