DOS Command

i had answered similar question in:
http://hk.knowledge.yahoo.com/question/?qid=7007050606229

try to use system variable %DATE% to get the current date.

if u want to output date in format YYMMDD, u need to know the default date format.

if the date format is dd/mm/yyyy day ( for example: 26/10/2007 Fri ), try this
echo %date:~8,2%%date:~3,2%%date:~0,2%


if the date format is yyyy/mm/dd day ( for example: 2007/10/26 Fri ), try this
echo %date:~2,2%%date:~5,2%%date:~8,2%

OK?

try this:

for /F "tokens=2-4 delims=/ " %%i in ('date /t') do set yyyymmdd=%%k%%i%%j
echo %yyyymmdd%