好易,係人都知

方法一：通分母
(x﹣1)/2 = (x+1)/3 + 1
(x﹣1)/2 = (x+1)/3 + 3/3
(x﹣1)/2 = (x+1+3)/3
(x﹣1)/2 = (x+4)/3
3(x﹣1) = 2(x+4)
3x﹣3 = 2x+8
x = 11

方法二：全式乘6
(x﹣1)/2 = (x+1)/3 + 1
6[(x﹣1)/2] = 6[(x+1)/3 + 1]
3(x﹣1) = 2(x+1)+6
3x﹣3 = 2x+2+6
x = 11

x-1 x+1
一一 = 一一 +1
2 3
2x/23=一一 +1
2x/23=(2x-23)/23+1
2x=23(2x-23)/23+23
2x=2x-23+23
x=任何數值

(x-1)/2=(x+1)/3 + 1
3(x-1)=2(x+1)+6
3x-3=2x+2+6
x=2+6+3
x=11