✔ 最佳答案
a^4+b^4 cannot be factorized.
a^6-b^6
=(a^2)^3-(b^2)^3
=(a^2-b^2)(a^4+a^2*b^2+b^4)
=(a+b)(a-b)(a^4+2a^2*b^2-a^2*b^2+b^4)
=(a+b)(a-b)[(a^2+b^2)^2-(ab)^2]
=(a+b)(a-b)(a^2+ab+b^2)(a^2-ab+b^2)
a^10-b^10
=(a^5)^2-(b^5)^2
=(a^5+b^5)(a^5-b^5)
=(a+b)(a^4-a^3*b+a^2*b^2-a*b^3+b^4)(a-b)(a^4+a^3*b+a^2*b^2+a*b^3+b^4)