請列式
(c-d)-(c+d)
thank!!
一條有趣的問題?
2007-10-24 5:50 am
回答 (8)
2007-10-24 5:57 am
✔ 最佳答案
（ｃ－ｄ）－（ｃ＋ｄ）將佢負負得正 負正得負分解先
變成
ｃ－ｄ－ｃ－ｄ
再排反好個次序
ｃ－ｃ－ｄ－ｄ
＝－２ｄ
＝＝＝＝＝＝＝＝＝＝＝＝
變反做數字
ｃ＝１ｃ
ｄ＝１ｄ
（１ｃ－１ｄ）－（１ｃ＋１ｄ）
＝１ｃ－１ｃ－１ｄ－１ｄ
＝０ｃ－２ｄ
＝－２ｄ／／
－－－－－－－－－－－
＝ ＝正常應該係咁．．
參考: ｍｙｓｅｌｆ
2007-10-24 6:06 am
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
2007-10-24 5:56 am
(c-d)-(c+d)
=c-d-c-d
=0
=c-d-c-d
=0
2007-10-24 5:55 am
(c-d)-(c+d)
=c-d-c-d
=-2d
=c-d-c-d
=-2d
2007-10-24 5:55 am
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
= c-d-c-d
= c-c-d-d
= -2d
2007-10-24 5:53 am
(c-d)-(c+d)
= c-d-c-d
= c-c-d-d
= -2d
= c-d-c-d
= c-c-d-d
= -2d
收錄日期: 2021-04-13 14:06:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071023000051KK03727