Factorize the following expression:
1) x^2-y^2+5x-5y
2) x^2-4y^2-3x-6y
3) (x^2-2xy+y^2)-z^2
4) (x^2+4xy+4y^2)-4z^2
F.2 math factorize
2007-10-24 3:18 am
回答 (3)
2007-10-24 3:59 am
1)x^2-y^2+5x-5y
= (x-y)(x+y+5)
2)x^2-4y^2-3x-6y
= (x+2y)(x-2y-3)
3)(x^2-2xy+y^2)-z^2
= (x-y+z)(x-y-z)
4)(x^2+4xy+4y^2)-4z^2
=(x+2y-2z)(x+2y+2z)
Hope I can help you!!~
= (x-y)(x+y+5)
2)x^2-4y^2-3x-6y
= (x+2y)(x-2y-3)
3)(x^2-2xy+y^2)-z^2
= (x-y+z)(x-y-z)
4)(x^2+4xy+4y^2)-4z^2
=(x+2y-2z)(x+2y+2z)
Hope I can help you!!~
2007-10-24 3:29 am
1) =(x+y)(x-y)+5(x-y)
=(x-y)(x+y+5)
2) =(x+2y)(x-2y)-3(x+2y)
=(x+2y)(x-2y-3)
3) =(x-y)^2 - z^2
=[(x-y)+z][(x-y)-z]
=(x-y+z)(x-y-z)
4) =(x+2y)^2 - (2z)^2
=[(x+2y)+2z][(x+2y)-2z]
=(x+2y+2z)(x+2y-2z)
=(x-y)(x+y+5)
2) =(x+2y)(x-2y)-3(x+2y)
=(x+2y)(x-2y-3)
3) =(x-y)^2 - z^2
=[(x-y)+z][(x-y)-z]
=(x-y+z)(x-y-z)
4) =(x+2y)^2 - (2z)^2
=[(x+2y)+2z][(x+2y)-2z]
=(x+2y+2z)(x+2y-2z)
參考: 自己
2007-10-24 3:26 am
1)
x^2-y^2+5x-5y
= (x-y)(x+y+5)
2)
x^2-4y^2-3x-6y
= (x+2y)(x-2y)-3(x+2y)
= (x+2y)(x-2y-3)
3)
(x^2-2xy+y^2)-z^2
= (x-y)^2-z^2
= (x-y+z)(x-y-z)
4)
(x^2+4xy+4y^2)-4z^2
= (x+2y)^2-(2z)^2
=(x+2y-2z)(x+2y+2z)
2007-10-23 19:27:21 補充：
1) x^2-y^2 5x-5y=(x y)(x-y) 5(x-y)= (x-y)(x y 5)
2007-10-23 19:27:45 補充：
1)x^2-y^2 5x-5y=(x y)(x-y) 5(x-y)= (x-y)(x y 5)
2007-10-23 19:28:04 補充：
1)x^2-y^2+5x-5y=(x+y)(x-y) 5(x-y)= (x-y)(x+y 5)
x^2-y^2+5x-5y
= (x-y)(x+y+5)
2)
x^2-4y^2-3x-6y
= (x+2y)(x-2y)-3(x+2y)
= (x+2y)(x-2y-3)
3)
(x^2-2xy+y^2)-z^2
= (x-y)^2-z^2
= (x-y+z)(x-y-z)
4)
(x^2+4xy+4y^2)-4z^2
= (x+2y)^2-(2z)^2
=(x+2y-2z)(x+2y+2z)
2007-10-23 19:27:21 補充：
1) x^2-y^2 5x-5y=(x y)(x-y) 5(x-y)= (x-y)(x y 5)
2007-10-23 19:27:45 補充：
1)x^2-y^2 5x-5y=(x y)(x-y) 5(x-y)= (x-y)(x y 5)
2007-10-23 19:28:04 補充：
1)x^2-y^2+5x-5y=(x+y)(x-y) 5(x-y)= (x-y)(x+y 5)
收錄日期: 2021-04-13 14:06:44
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