f2 maths 2

y/(x+2) = 8
y = 8(x+2)
y = 8x+16
y﹣16 = 8x
(y﹣16)/8 = x
x = (y﹣16)/8

3/(4x+2y) = 1
3 = 4x+2y
3﹣2y = 4x
x = (3﹣2y)/4

a = 2(c﹣b)/b
ab = 2c﹣2b
ab+2b = 2c
b(a+2) = 2c
b = 2c/(a+2)

1. y/x+2=8 [x]
y=8(x+2)
y/8=x+2
y/8-2=x

2. 3/4x+2y=1 [x]
3=4x+2y
3-2y=4x
3-2y/4=x

3. a=2(c-b)/b [b]
ab=2(c-b)
ab=2c-2b
ab+2b=2c
b(a+2)=2c <-因式分解
b=2c/a+2

y/(x+2) = 8
=> y = 8(x+2)
=> x = y/8 -2
=> x = (y - 16)/8

3/(4x+2y) = 1
3 = 4x +2y
4x = 3 - 2y
x = (3-2y)/4

a = 2(c-b)/b
ab = 2c - 2b
ab+2b = 2c
b (a+2) = 2c
b = 2c / (a+2)