請幫手解決呢條arithmetic sequence 問題

2007-10-21 7:48 pm
if a,b , c are thre sides of a right -angled triangle and that a,b ,c are in an arithmetic sequence, prove that a:b:c=3:4:5

回答 (1)

2007-10-21 10:04 pm
✔ 最佳答案
As a, b, c are in arithmetic sequence,
let a = k-m, b = k and c = k+m.
(k-m)^2 + k^2 = (k+m)^2
2k^2 - 2km + m^2 = k^2 + 2km + m^2
k^2 - 4km = 0
k(k-4m) = 0
k = 0 or 4m
The answer k = 0 is rejected because it is impossible for a side of triangle is 0.
Therefore, k = 4m
a = 4m - m = 3m, b = 4m and c = 5m
Therefore a:b:c = 3m:4m:5m = 3:4:5


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