factorize
2(a-b)^2-ab+a^2
maths
2007-10-21 5:47 am
回答 (4)
2007-10-21 5:54 am
✔ 最佳答案
2(a-b)^2-ab+a^2=2(a-b)^2-a(b-a)
=2(a-b)^2+a(a-b)
=(a-b)(2a-2b+a)
=(a-b)(3a-2b)
2007-10-21 6:12 am
2(a-b)^2-ab+a^2
= 2(a^2-2ab+b^2) - ab + a^2
= 2a^2 - 4ab + 2b^2 - ab + a^2
=3a^2 - 5ab + 2b^2
= 2(a^2-2ab+b^2) - ab + a^2
= 2a^2 - 4ab + 2b^2 - ab + a^2
=3a^2 - 5ab + 2b^2
2007-10-21 5:55 am
=2(a-b)^2-a(b-a)
=(a-b)[2(a-b)-a]
=(a-b)(2a-2b-a)
=(a-b)(a-2b)//
=(a-b)[2(a-b)-a]
=(a-b)(2a-2b-a)
=(a-b)(a-2b)//
2007-10-21 5:52 am
3a^2+2b^2-5ab
收錄日期: 2021-04-13 14:11:22
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071020000051KK05102