1+2+3+...+n = [n(n+1)]/2 *呢個formula叫咩? (10點!!)

2007-10-20 12:53 am
1+2+3+...+n = [n(n+1)] /2

呢個formula 叫咩?
同埋係咪 mathematical concept?

回答 (2)

2007-10-20 1:23 am
✔ 最佳答案
Arithmetic progression
2007-10-20 8:36 am
等差數列(簡稱AP)


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