1+2+3+...+n = [n(n+1)]/2 *呢個formula叫咩? (10點!!)

[匿名]

2007-10-20 12:53 am

1+2+3+...+n = [n(n+1)] /2

呢個formula 叫咩?
同埋係咪 mathematical concept?

回答 (2)

枝枝

2007-10-20 1:23 am

✔ 最佳答案

Arithmetic progression

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[匿名]

2007-10-20 8:36 am

等差數列(簡稱AP)

👍 0 👎 0

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