Please show the answer step by step.
(v-2u)^2 - (2u-v)(u+2v) - 2v+4u
Factorize it.
F.2 Factorization
2007-10-20 12:39 am
回答 (4)
2007-10-20 12:51 am
✔ 最佳答案
(v-2u)^2 - (2u -v)(u+2v) - 2v+4u=(v-2u)^2 + (v -2u)(u+2v) - 2(v -2u)
=(v -2u) [v -2u +u + 2v -2]
=(v -2u) [3v -u -2]
=3v^2 -uv -2v -6uv +2u^2 +4u
=3v^2 -2v -7uv +4u +2u^2
參考: myself
2007-10-28 9:53 pm
真係好感謝你,不過我覺得你最後果兩個steps可以唔要左佢
2007-10-23 3:09 am
大佬
Factorize唔同Simplify
亂咁教人 ! ! !
Factorize唔同Simplify
亂咁教人 ! ! !
2007-10-22 5:52 am
(v-2u)^2 - (2u-v)(u+2v) - 2v+4u
=(v-2u)^2 - {-(v-2u)} (u+2v) -2v+4u
= (v-2u)^2 + (v-2u)(u+2v) -2v+4u
= (v-2u) {v-2u+u+2v} -2v+4u
= (v-2u)(3v-u)- 2(v-2u)
=(v-2u)(3v-u-2)
=(v-2u)^2 - {-(v-2u)} (u+2v) -2v+4u
= (v-2u)^2 + (v-2u)(u+2v) -2v+4u
= (v-2u) {v-2u+u+2v} -2v+4u
= (v-2u)(3v-u)- 2(v-2u)
=(v-2u)(3v-u-2)
參考: maths book
收錄日期: 2021-04-23 13:54:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071019000051KK02965