9% 醋酸 約 pH 值幾多?

Ka = [H+][CH3COO-] / [CH3COOH]
100% 醋酸 = 17.48 M
9% 醋酸(容積百分比) = 1.57 M
Ka(醋酸) = 1.7 * 10^-5 per mol per dm^3
1.7 * 10^-5 = [H+]^2 / 1.57
[H+]^2 = 2.669 * 10^-5
[H+] = 5.166 * 10^-3
pH(9% 醋酸) = - log(5.166 * 10^-3)
= 2.29
希望解答到你 ^^

醋酸 約 pH = 2
所以
9% 醋酸 約 pH = 3