多項式簡介
分解為因式
1.ac+bc-ad-bd
2.7ap+2p-14a-4
3.15bx-3b+5ax-a
4.xyp-xyp+3p-3p
5.x^2
-2c-2x+cx
中二數學(~急~)
2007-10-19 2:43 am
回答 (7)
2007-10-19 2:53 am
✔ 最佳答案
1.ac+bc-ad-bd=c(a+b) -d(a+b)
=(a+b)(c -d)
2.7ap+2p-14a-4
=p(7a+2) -2(7a+2)
=(7a+2)(p -2)
3.15bx-3b+5ax-a
=3b(5x -1)+a(5x -1)
=(5x -1)(3b+a)
4.xyp-xyp+3p-3p
=(xyp-xyp)+(3p -3p)
=0
5.x^2-2c-2x+cx
=(x^2 -2x)+(cx -2c)
=x(x -2)+c(x -2)
=(x -2)(x+c)
參考: myself
2007-10-19 3:07 am
1.ac+bc-ad-bd
=ac-ad+bc-bd
=a(c-d)+b(c-d)
=(c-d)(a+b)
2.7ap+2p-14a-4
=p(7a+2)-2(7a+2)
=(7a+2)(p-2)
3.15bx-3b+5ax-a
=3b(5x-1)+a(5x-1)
=(5x-1)(3b+a)
4.xyp-xyp+3p-3p
=0
5.x^2-2c-2x+cx
=cx-2c+x^2-2x
=c(x-2)+x(x-2)
=(x-2)(c+x)
=ac-ad+bc-bd
=a(c-d)+b(c-d)
=(c-d)(a+b)
2.7ap+2p-14a-4
=p(7a+2)-2(7a+2)
=(7a+2)(p-2)
3.15bx-3b+5ax-a
=3b(5x-1)+a(5x-1)
=(5x-1)(3b+a)
4.xyp-xyp+3p-3p
=0
5.x^2-2c-2x+cx
=cx-2c+x^2-2x
=c(x-2)+x(x-2)
=(x-2)(c+x)
2007-10-19 3:04 am
1. ac+bc-ad-bd
= c(a + b) - d(a + b)
= (a + b) (c - d)
2. 7ap+2p-14a-4
= 7ap - 14a + 2p - 4
= 7a(p - 2) + 2(p - 2)
= (7a + 2) (p - 2)
3. 15bx-3b+5ax-a
= 3b(5x - 1) + a(5x - 1)
= (3b + 1) (5x - 1)
4. xyp-xyp+3p-3p
= (xyp-xyp) + (3p-3p)
= 0 + 0
= 0
5. x^2-2c-2x+cx
= x^2 - 2x + cx - 2c
= x(x - 2) + c(x - 2)
= (x + c) (x - 2)
= c(a + b) - d(a + b)
= (a + b) (c - d)
2. 7ap+2p-14a-4
= 7ap - 14a + 2p - 4
= 7a(p - 2) + 2(p - 2)
= (7a + 2) (p - 2)
3. 15bx-3b+5ax-a
= 3b(5x - 1) + a(5x - 1)
= (3b + 1) (5x - 1)
4. xyp-xyp+3p-3p
= (xyp-xyp) + (3p-3p)
= 0 + 0
= 0
5. x^2-2c-2x+cx
= x^2 - 2x + cx - 2c
= x(x - 2) + c(x - 2)
= (x + c) (x - 2)
2007-10-19 2:59 am
1.ac+bc-ad-bd
=ac-ad+bc-bd
=a(c-d)+b(c-d)
=(c-d)(a+b)
2.7ap+2p-14a-4
=7ap-14a+2p-4
=7a(p-2)+2(p-2)
(p-2)(7a+2)
3.15bx-3b+5ax-a
=3b(5x-1)+a(5x-1)
=(5x-1)(3b+a)
4.xyp-xyp+3p-3p
=3p-xyp-3p+xyp
=p(3-xy)-p(3-xy)
=(3-xy)
5.x^2-2c-2x+cx
= -2c-2x+x^2+cx
=-2(c+x)+x(c+x)
(c+x)(-2+x)
=ac-ad+bc-bd
=a(c-d)+b(c-d)
=(c-d)(a+b)
2.7ap+2p-14a-4
=7ap-14a+2p-4
=7a(p-2)+2(p-2)
(p-2)(7a+2)
3.15bx-3b+5ax-a
=3b(5x-1)+a(5x-1)
=(5x-1)(3b+a)
4.xyp-xyp+3p-3p
=3p-xyp-3p+xyp
=p(3-xy)-p(3-xy)
=(3-xy)
5.x^2-2c-2x+cx
= -2c-2x+x^2+cx
=-2(c+x)+x(c+x)
(c+x)(-2+x)
參考: 我也是中二的!!
2007-10-19 2:55 am
1.ac+bc-ad-bd
=c(a+b) -d(a+b)
=(a+b)(c -d)
2.7ap+2p-14a-4
=p(7a+2) -2(7a+2)
=(7a+2)(p -2)
3.15bx-3b+5ax-a
=3b(5x -1)+a(5x -1)
=(5x -1)(3b+a)
4.xyp-xyp+3p-3p
=(xyp-xyp)+(3p -3p)
=0
5.x^2-2c-2x+cx
=(x^2 -2x)+(cx -2c)
=x(x -2)+c(x -2)
=(x -2)(x+c)
=c(a+b) -d(a+b)
=(a+b)(c -d)
2.7ap+2p-14a-4
=p(7a+2) -2(7a+2)
=(7a+2)(p -2)
3.15bx-3b+5ax-a
=3b(5x -1)+a(5x -1)
=(5x -1)(3b+a)
4.xyp-xyp+3p-3p
=(xyp-xyp)+(3p -3p)
=0
5.x^2-2c-2x+cx
=(x^2 -2x)+(cx -2c)
=x(x -2)+c(x -2)
=(x -2)(x+c)
參考: 自己
2007-10-19 2:55 am
1. ac+bc-ad-bd
= (ac-ad)+(bc-bd)
= a(c-d) + b(c-d)
= (c-d) (a+b)
2. 7ap+2p-14a-4
= (7ap-14a)+(2p-4)
= 7a(p-2) + 2 (p-2)
= (p-2) (7a+2)
3. 15bx-3b+5ax-a
= (15bx+5ax) - (3b+a)
= 5x(3b+a) - 1(3b+a)
= (3b+a) (5x-1)
4. xyp-xyp+3p-3p
= 0
5. x^2-2c-2x+cx
= (cx -2c)-(2x -x^2)
= c(x-2) - x (2-x)
= c(x-2) + x (x-2)
= (x-2) (c+x)
唔知對不對呢?
不過第4條就怪怪地... XDD
= (ac-ad)+(bc-bd)
= a(c-d) + b(c-d)
= (c-d) (a+b)
2. 7ap+2p-14a-4
= (7ap-14a)+(2p-4)
= 7a(p-2) + 2 (p-2)
= (p-2) (7a+2)
3. 15bx-3b+5ax-a
= (15bx+5ax) - (3b+a)
= 5x(3b+a) - 1(3b+a)
= (3b+a) (5x-1)
4. xyp-xyp+3p-3p
= 0
5. x^2-2c-2x+cx
= (cx -2c)-(2x -x^2)
= c(x-2) - x (2-x)
= c(x-2) + x (x-2)
= (x-2) (c+x)
唔知對不對呢?
不過第4條就怪怪地... XDD
2007-10-19 2:55 am
1.ac + bc + ad + bd
=a(c+d) + b(c+d)
=(a+b)(c+d)
2.7ap + 2p - 14a - 4
=7a(p - 2) + 2(p - 2)
=( 7a + 2 ) ( p - 2 )
3.15bx - 3b + 5ax - a
=3b ( 5x - 1) + a ( 5x - 1)
=( 3b + a ) ( 5x - 1 )
4.xyp - xyp + 3p - 3p
= 0
5.x² - 2c - 2x + cx
= x ( x - 2 ) + c ( x - 2 )
=( x + c ) ( x - 2 )
=a(c+d) + b(c+d)
=(a+b)(c+d)
2.7ap + 2p - 14a - 4
=7a(p - 2) + 2(p - 2)
=( 7a + 2 ) ( p - 2 )
3.15bx - 3b + 5ax - a
=3b ( 5x - 1) + a ( 5x - 1)
=( 3b + a ) ( 5x - 1 )
4.xyp - xyp + 3p - 3p
= 0
5.x² - 2c - 2x + cx
= x ( x - 2 ) + c ( x - 2 )
=( x + c ) ( x - 2 )
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