我要埋成個步驟同埋點解咁解呢條式!唔該!
7K-(9K-16)=14-(19-K)
代數式....幫我解喇!!
2007-10-19 2:33 am
回答 (3)
2007-10-19 2:42 am
✔ 最佳答案
7K-9K+16=14-19+K7K-9K-K=14-19-16
-3K=-21
K=-21/-3
K=7
參考: My ability
2007-10-19 3:06 am
7K-(9K-16)=14-(19-K)
7K-9K+16=14-19+K
-2K+16=-5+K
-3K+16=-5
-3K=-21
K=-21/-3
K7
7K-9K+16=14-19+K
-2K+16=-5+K
-3K+16=-5
-3K=-21
K=-21/-3
K7
參考: me
2007-10-19 2:50 am
7K-(9K-16)=14-(19-K)
9k-16=14-(19-k)-7k
-14=(19-k)-7k-(9k-16)
-14=19-k-7k-9k+16
-14-16=19-k-7k-9k+16-16
-30=19-k-7k-9k
-49=-18k
-49/-18=-18k/18
k=49over18
9k-16=14-(19-k)-7k
-14=(19-k)-7k-(9k-16)
-14=19-k-7k-9k+16
-14-16=19-k-7k-9k+16-16
-30=19-k-7k-9k
-49=-18k
-49/-18=-18k/18
k=49over18
收錄日期: 2021-04-13 19:40:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20071018000051KK02426