(a) (integral 8 1) e^3√x / 3√x^2 dt
(b) (integral 2 1) sint / t dt
Maths(INTEGRAL by substitution)
2007-10-18 8:42 pm
回答 (2)
2007-10-18 8:56 pm
✔ 最佳答案
put u = 3√xdu = 1/3 (3√x^2 ) dx
when x = 1, u = 1; when x = 8, u = 2
(integral 8 1) e^3√x / 3√x^2 dx
(integral 2 1) 3 e^u du = 3(e^2 - e)
第2題有冇打錯題目?應做唔到
2007-10-18 9:52 pm
收錄日期: 2021-04-13 19:32:20
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