問2次咸數解以下.詳細 thx!

2007-10-18 5:17 am
求下面2次咸數,判斷是極大定極小值
1.y= -x^2-10x-7
2.y= 6x^2+2x+1
求下面2次咸數既略圖
1.y=x^2-8x-2
2.y=3x^2-2x-1

唔該晒大家一直來的解答我自問數學白痴.我有努力過但係都唔明
希望有熱心人士幫我在電腦上/msn/icq 補數學.詳細解答.多謝

回答 (2)

2007-10-21 2:23 am
✔ 最佳答案
1. y = -x2 – 10x – 7
y = -(x2 + 10x )– 7
y = -[x2 + 10x+ (5)2– (5)2] – 7
y = -(x + 5)2+25– 7
y = -(x + 5)2 + 18
∴y的極大值是18.
2. y = 6x2 + 2x + 1
y = 6(x2 + 2x(1/6) ]+ 1
y = 6[x2 + (1/3)x + (1 / 6)2– (1 / 6)2]+ 1
y = 6(x + 1/6)2–6/36+ 1
y = 6(x + 1/6) – 1 / 6 + 1
y = 6(x + 1/6)2 + 5 / 6
∴y的極小值是5/6.


圖片參考:http://i182.photobucket.com/albums/x4/A_Hepburn_1990/ScreenHunter_02Oct182009.jpg?t=1192709564




圖片參考:http://i182.photobucket.com/albums/x4/A_Hepburn_1990/ScreenHunter_03Oct182011.jpg?t=1192709581
2007-10-18 7:25 am
咸數不是數學!!

咸數是指甚麼?

y= -x^2-10x-7
y= 6x^2+2x+1

以上不是咸數!!


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