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🎓 學業台小學及中學教育

[匿名]

2007-10-18 3:02 am

[(6-2c)+(3d+2)]x(2c+d)] 除以２

更新1:

係化簡唔該

更新2:

化簡比埋式

回答 (3)

[匿名]

2007-10-18 3:56 am

✔ 最佳答案

[(6-2c+ 3d+2)x(2c+d)]/2
=(3d-2c+8)(2c+d)x1/2
=(6cd-4c'2 +16c+3d'2-2cd+8d)x1/2
抽common factor 2
=3/2d'2 -2c'2 +2cd +8c +4d

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[匿名]

2007-10-18 3:30 am

=(6-2c+3d+2)(2c+d)/2
=(8-2c+3d)(2c+d)/2
=(16c-4c^2+8d+4cd+3d^2)/2
=8c-2c^2+4d+2cd+3/2d^2

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用戶144908

2007-10-18 3:14 am

The answer is 8c-2c(suqare)+2cd+4d+1.5d(square)

參考: me

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