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5y-4(3y-2)=-20
2{p-2(p+1)}-1=8p+25
5(y+4)-6(8+3y)=-2
回答 (4)
✔ 最佳答案
5y-4(3y-2)=-20
5y-(12y-8)=-20
5y-12y+8=-20
-7y=-28
y=4
2{p-2(p+1)}-1=8p+25
2{p-(2p+2)}-1=8p+25
2{p-2p-2}-1=8p+25
2{-p-2}-1=8p+25
-2p-4-1=8p+25
-10p=30
p=-3
5(y+4)-6(8+3y)=-2
5y+20-(48+18y)=-2
5y+20-48-18y=-2
-13y=-2-20+48
-13y=26
y=-2
5y-4(3y-2)=-20
5y-4(3y-2)=-20
5y-12y+8=-20
-7y+8=-20
-7y=-28
7y=28
y=4
2{p-2(p+1)}-1=8p+25
2(p-2p-2)-1=8p+25
2p-4p-4-1=8p+25
-2p-5=8p+25
-10p=30
-p=3
p=-3
5(y+4)-6(8+3y)=-2
5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
-13y-28=-2
-13y=26
-y=2
y=-2
參考: My maths knowledge
5y-4(3y-2)=-20
5Y-12y-8 =-20
20-8 = 12y-5y
12 = 7y
12/7 = y
y = 1 5/7
2{p-2(p+1)}-1=8p+25
2(p-2p+2)-1=8p+25
2p-4p+4-1=8p+25
-2p+3=8p+25
3-25=8p+2p
-22=10p
-22/10=p
p=-11/5
p=-2 1/5
5(y+4)-6(8+3y)=-2
5y+20-48+18y=-2
5y+18y=48-20-2
23y=26
y=26/23
y=1 3/23
5y-4(3y-2)=-20
5y-12y+8=-20
7y=28
y=4
2{p-2(p+1)}-1=8p+25
2{p-2p-2}-1=8p+25
2p-4p-4-1=8p+25
10p=30
p=3
5(y+4)-6(8+3y)=-2
5y+20-48-18y=-2
13y=26
y=2
參考: myself
收錄日期: 2021-04-13 19:30:43
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